3/4=-6/(c-3)^3

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Solution for 3/4=-6/(c-3)^3 equation:


D( c )

(c-3)^3 = 0

(c-3)^3 = 0

(c-3)^3 = 0

c-3 = 0 // + 3

c = 3

c in (-oo:3) U (3:+oo)

3/4 = -6/((c-3)^3) // + -6/((c-3)^3)

3/4-(-6/((c-3)^3)) = 0

6*(c-3)^-3+3/4 = 0

6/((c-3)^3)+3/4 = 0

(4*6)/(4*(c-3)^3)+(3*(c-3)^3)/(4*(c-3)^3) = 0

3*(c-3)^3+4*6 = 0

3*c^3-27*c^2+81*c-57 = 0

3*c^3-27*c^2+81*c-57 = 0

3*(c^3-9*c^2+27*c-19) = 0

c^3-9*c^2+27*c-19 = 0

{ 1, -1, 19, -19 }

1

c = 1

c^3-9*c^2+27*c-19 = 0

1

c-1

c^2-8*c+19

c^3-9*c^2+27*c-19

c-1

c^2-c^3

27*c-8*c^2-19

8*c^2-8*c

19*c-19

19-19*c

0

c^2-8*c+19 = 0

DELTA = (-8)^2-(1*4*19)

DELTA = -12

DELTA < 0

c in { 1}

3*(c-1) = 0

(3*(c-1))/(4*(c-3)^3) = 0

(3*(c-1))/(4*(c-3)^3) = 0 // * 4*(c-3)^3

3*(c-1) = 0

c-1 = 0 // + 1

c = 1

c = 1

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